Integration of

1
x2−a2
by trigonometric substitution?∫
1
x2−a2
dx
Now, I know this can be done by splitting the function into two integrable functions,
1
2a
∫(
1
x−a
−
1
x+a
)dx
And then doing the usual stuff.
My question is, how can we do this by using trigonometric substitution?
The only thing that gets in my mind is x=asecθ
, but then got stuck on proceeding further.
Any help would be appreciated.

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